Optimal. Leaf size=257 \[ -\frac {\sqrt [4]{-1} \sqrt {a} \sqrt {d} \left (15 c^2-10 i c d-7 d^2\right ) \tanh ^{-1}\left (\frac {(-1)^{3/4} \sqrt {d} \sqrt {a+i a \tan (e+f x)}}{\sqrt {a} \sqrt {c+d \tan (e+f x)}}\right )}{4 f}-\frac {i \sqrt {2} \sqrt {a} (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d} \sqrt {a+i a \tan (e+f x)}}\right )}{f}+\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f} \]
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Rubi [A]
time = 0.68, antiderivative size = 257, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 9, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.281, Rules used = {3641, 3678,
3682, 3625, 214, 3680, 65, 223, 212} \begin {gather*} -\frac {\sqrt [4]{-1} \sqrt {a} \sqrt {d} \left (15 c^2-10 i c d-7 d^2\right ) \tanh ^{-1}\left (\frac {(-1)^{3/4} \sqrt {d} \sqrt {a+i a \tan (e+f x)}}{\sqrt {a} \sqrt {c+d \tan (e+f x)}}\right )}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}+\frac {d (7 c-i d) \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}-\frac {i \sqrt {2} \sqrt {a} (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d} \sqrt {a+i a \tan (e+f x)}}\right )}{f} \end {gather*}
Antiderivative was successfully verified.
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Rule 65
Rule 212
Rule 214
Rule 223
Rule 3625
Rule 3641
Rule 3678
Rule 3680
Rule 3682
Rubi steps
\begin {align*} \int \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{5/2} \, dx &=\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}-\frac {\int \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (-\frac {1}{2} a \left (4 c^2-i c d-3 d^2\right )-\frac {1}{2} a (7 c-i d) d \tan (e+f x)\right ) \, dx}{2 a}\\ &=\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}-\frac {\int \frac {\sqrt {a+i a \tan (e+f x)} \left (-\frac {1}{4} a^2 \left (8 c^3-9 i c^2 d-14 c d^2+i d^3\right )-\frac {1}{4} a^2 d \left (15 c^2-10 i c d-7 d^2\right ) \tan (e+f x)\right )}{\sqrt {c+d \tan (e+f x)}} \, dx}{2 a^2}\\ &=\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}+(c-i d)^3 \int \frac {\sqrt {a+i a \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}} \, dx+\frac {\left (d \left (15 i c^2+10 c d-7 i d^2\right )\right ) \int \frac {(a-i a \tan (e+f x)) \sqrt {a+i a \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}} \, dx}{8 a}\\ &=\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}+\frac {\left (2 a^2 (i c+d)^3\right ) \text {Subst}\left (\int \frac {1}{a c-i a d-2 a^2 x^2} \, dx,x,\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {a+i a \tan (e+f x)}}\right )}{f}+\frac {\left (a d \left (15 i c^2+10 c d-7 i d^2\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+i a x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{8 f}\\ &=-\frac {i \sqrt {2} \sqrt {a} (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d} \sqrt {a+i a \tan (e+f x)}}\right )}{f}+\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}+\frac {\left (d \left (15 c^2-10 i c d-7 d^2\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c+i d-\frac {i d x^2}{a}}} \, dx,x,\sqrt {a+i a \tan (e+f x)}\right )}{4 f}\\ &=-\frac {i \sqrt {2} \sqrt {a} (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d} \sqrt {a+i a \tan (e+f x)}}\right )}{f}+\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}+\frac {\left (d \left (15 c^2-10 i c d-7 d^2\right )\right ) \text {Subst}\left (\int \frac {1}{1+\frac {i d x^2}{a}} \, dx,x,\frac {\sqrt {a+i a \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{4 f}\\ &=-\frac {\sqrt [4]{-1} \sqrt {a} \sqrt {d} \left (15 c^2-10 i c d-7 d^2\right ) \tanh ^{-1}\left (\frac {(-1)^{3/4} \sqrt {d} \sqrt {a+i a \tan (e+f x)}}{\sqrt {a} \sqrt {c+d \tan (e+f x)}}\right )}{4 f}-\frac {i \sqrt {2} \sqrt {a} (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {a} \sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d} \sqrt {a+i a \tan (e+f x)}}\right )}{f}+\frac {(7 c-i d) d \sqrt {a+i a \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 f}+\frac {d \sqrt {a+i a \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{2 f}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(539\) vs. \(2(257)=514\).
time = 6.30, size = 539, normalized size = 2.10 \begin {gather*} \frac {\left (\frac {1}{8}+\frac {i}{8}\right ) \sqrt {a+i a \tan (e+f x)} \left (-\frac {\cos (e+f x) \left (\sqrt {d} \left (15 c^2-10 i c d-7 d^2\right ) \left (\log \left (\frac {(2+2 i) e^{\frac {i e}{2}} \left (c+i d-i c e^{i (e+f x)}-d e^{i (e+f x)}+(1+i) \sqrt {d} \sqrt {1+e^{2 i (e+f x)}} \sqrt {c-\frac {i d \left (-1+e^{2 i (e+f x)}\right )}{1+e^{2 i (e+f x)}}}\right )}{d^{3/2} \left (-15 c^2+10 i c d+7 d^2\right ) \left (i+e^{i (e+f x)}\right )}\right )-\log \left (-\frac {(2+2 i) e^{\frac {i e}{2}} \left (c+i d+i c e^{i (e+f x)}+d e^{i (e+f x)}+(1+i) \sqrt {d} \sqrt {1+e^{2 i (e+f x)}} \sqrt {c-\frac {i d \left (-1+e^{2 i (e+f x)}\right )}{1+e^{2 i (e+f x)}}}\right )}{d^{3/2} \left (-15 c^2+10 i c d+7 d^2\right ) \left (-i+e^{i (e+f x)}\right )}\right )\right )+(8+8 i) (c-i d)^{5/2} \log \left (2 \left (\sqrt {c-i d} \cos (e+f x)+i \sqrt {c-i d} \sin (e+f x)+\sqrt {1+\cos (2 (e+f x))+i \sin (2 (e+f x))} \sqrt {c+d \tan (e+f x)}\right )\right )\right )}{\sqrt {1+\cos (2 (e+f x))+i \sin (2 (e+f x))}}+(1-i) d \sqrt {c+d \tan (e+f x)} (9 c-i d+2 d \tan (e+f x))\right )}{f} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 2129 vs. \(2 (202 ) = 404\).
time = 0.57, size = 2130, normalized size = 8.29
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(2130\) |
default | \(\text {Expression too large to display}\) | \(2130\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 1151 vs. \(2 (201) = 402\).
time = 1.31, size = 1151, normalized size = 4.48 \begin {gather*} -\frac {4 \, \sqrt {2} {\left (f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )} \sqrt {-\frac {a c^{5} - 5 i \, a c^{4} d - 10 \, a c^{3} d^{2} + 10 i \, a c^{2} d^{3} + 5 \, a c d^{4} - i \, a d^{5}}{f^{2}}} \log \left (-\frac {{\left (i \, \sqrt {2} f \sqrt {-\frac {a c^{5} - 5 i \, a c^{4} d - 10 \, a c^{3} d^{2} + 10 i \, a c^{2} d^{3} + 5 \, a c d^{4} - i \, a d^{5}}{f^{2}}} e^{\left (i \, f x + i \, e\right )} - \sqrt {2} {\left (c^{2} - 2 i \, c d - d^{2} + {\left (c^{2} - 2 i \, c d - d^{2}\right )} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \sqrt {\frac {{\left (c - i \, d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + c + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{c^{2} - 2 i \, c d - d^{2}}\right ) - 4 \, \sqrt {2} {\left (f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )} \sqrt {-\frac {a c^{5} - 5 i \, a c^{4} d - 10 \, a c^{3} d^{2} + 10 i \, a c^{2} d^{3} + 5 \, a c d^{4} - i \, a d^{5}}{f^{2}}} \log \left (-\frac {{\left (-i \, \sqrt {2} f \sqrt {-\frac {a c^{5} - 5 i \, a c^{4} d - 10 \, a c^{3} d^{2} + 10 i \, a c^{2} d^{3} + 5 \, a c d^{4} - i \, a d^{5}}{f^{2}}} e^{\left (i \, f x + i \, e\right )} - \sqrt {2} {\left (c^{2} - 2 i \, c d - d^{2} + {\left (c^{2} - 2 i \, c d - d^{2}\right )} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \sqrt {\frac {{\left (c - i \, d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + c + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{c^{2} - 2 i \, c d - d^{2}}\right ) - 2 \, \sqrt {2} {\left (3 \, {\left (3 \, c d - i \, d^{2}\right )} e^{\left (3 i \, f x + 3 i \, e\right )} + {\left (9 \, c d + i \, d^{2}\right )} e^{\left (i \, f x + i \, e\right )}\right )} \sqrt {\frac {{\left (c - i \, d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + c + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} + {\left (f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )} \sqrt {\frac {225 i \, a c^{4} d + 300 \, a c^{3} d^{2} - 310 i \, a c^{2} d^{3} - 140 \, a c d^{4} + 49 i \, a d^{5}}{f^{2}}} \log \left (\frac {{\left (\sqrt {2} {\left (15 \, c^{2} - 10 i \, c d - 7 \, d^{2} + {\left (15 \, c^{2} - 10 i \, c d - 7 \, d^{2}\right )} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \sqrt {\frac {{\left (c - i \, d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + c + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} + 2 i \, f \sqrt {\frac {225 i \, a c^{4} d + 300 \, a c^{3} d^{2} - 310 i \, a c^{2} d^{3} - 140 \, a c d^{4} + 49 i \, a d^{5}}{f^{2}}} e^{\left (i \, f x + i \, e\right )}\right )} e^{\left (-i \, f x - i \, e\right )}}{15 \, c^{2} - 10 i \, c d - 7 \, d^{2}}\right ) - {\left (f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )} \sqrt {\frac {225 i \, a c^{4} d + 300 \, a c^{3} d^{2} - 310 i \, a c^{2} d^{3} - 140 \, a c d^{4} + 49 i \, a d^{5}}{f^{2}}} \log \left (\frac {{\left (\sqrt {2} {\left (15 \, c^{2} - 10 i \, c d - 7 \, d^{2} + {\left (15 \, c^{2} - 10 i \, c d - 7 \, d^{2}\right )} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \sqrt {\frac {{\left (c - i \, d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + c + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} - 2 i \, f \sqrt {\frac {225 i \, a c^{4} d + 300 \, a c^{3} d^{2} - 310 i \, a c^{2} d^{3} - 140 \, a c d^{4} + 49 i \, a d^{5}}{f^{2}}} e^{\left (i \, f x + i \, e\right )}\right )} e^{\left (-i \, f x - i \, e\right )}}{15 \, c^{2} - 10 i \, c d - 7 \, d^{2}}\right )}{8 \, {\left (f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {i a \left (\tan {\left (e + f x \right )} - i\right )} \left (c + d \tan {\left (e + f x \right )}\right )^{\frac {5}{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \sqrt {a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{5/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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